0=99-2n^2-7n

Solution for 0=99-2n^2-7n equation:

0=99-2n^2-7n

We move all terms to the left:

0-(99-2n^2-7n)=0

We add all the numbers together, and all the variables

-(99-2n^2-7n)=0

We get rid of parentheses

2n^2+7n-99=0

a = 2; b = 7; c = -99;
Δ = b2-4ac
Δ = 72-4·2·(-99)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-29}{2*2}=\frac{-36}{4}
=-9
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+29}{2*2}=\frac{22}{4}
=5+1/2
$